/* * Knuth-Morris-Pratt string matcher (TypeScript) * * Copyright (c) 2021 Project Nayuki. (MIT License) * https://www.nayuki.io/page/knuth-morris-pratt-string-matching * * Permission is hereby granted, free of charge, to any person obtaining a copy of * this software and associated documentation files (the "Software"), to deal in * the Software without restriction, including without limitation the rights to * use, copy, modify, merge, publish, distribute, sublicense, and/or sell copies of * the Software, and to permit persons to whom the Software is furnished to do so, * subject to the following conditions: * - The above copyright notice and this permission notice shall be included in * all copies or substantial portions of the Software. * - The Software is provided "as is", without warranty of any kind, express or * implied, including but not limited to the warranties of merchantability, * fitness for a particular purpose and noninfringement. In no event shall the * authors or copyright holders be liable for any claim, damages or other * liability, whether in an action of contract, tort or otherwise, arising from, * out of or in connection with the Software or the use or other dealings in the * Software. */ // Searches for the given pattern string in the given text string using the Knuth-Morris-Pratt string matching algorithm. // If the pattern is found, this returns the index of the start of the earliest match in 'text'. Otherwise -1 is returned. function kmpSearch(pattern: string, text: string): number { if (pattern.length == 0) return 0; // Immediate match // Compute longest suffix-prefix table let lsp: Array = [0]; // Base case for (let i = 1; i < pattern.length; i++) { let j: number = lsp[i - 1]; // Start by assuming we're extending the previous LSP while (j > 0 && pattern.charAt(i) != pattern.charAt(j)) j = lsp[j - 1]; if (pattern.charAt(i) == pattern.charAt(j)) j++; lsp.push(j); } // Walk through text string let j: number = 0; // Number of chars matched in pattern for (let i = 0; i < text.length; i++) { while (j > 0 && text.charAt(i) != pattern.charAt(j)) j = lsp[j - 1]; // Fall back in the pattern if (text.charAt(i) == pattern.charAt(j)) { j++; // Next char matched, increment position if (j == pattern.length) return i - (j - 1); } } return -1; // Not found }